Wednesday, November 12, 2014

Quant Quiz

Directions—(Q. 1–5) Study the following information carefully and answer the questions given below it.
Out of the 45,000 candidates eligible for an Officer’s Post in a Public Sector Bank, 1350 candidates have prior experience of working in Public Sector Banks in rural areas only. One-fourth of the total number of candidates has prior experience of working in Public Sector Banks in urban areas only. 12% of the total number of candidates has prior experience of working in Private Sector Banks in urban areas only. 2% of the total number of candidates has prior experience of working in Private Sector Banks in rural areas only. 10800 candidates have worked in Public Sector Banks in both urban and rural areas. 15% of the total number of candidates has worked in both Public and Private Sector Banks in urban areas only. 1800 candidates have worked in both Public and Private Sector Banks in rural areas only. The remaining candidates have no prior experience of working in the Banking industry.


1. How many candidates have prior experience of working in rural areas (both Public Sector and Private Sector Banks together) ?
(1) 13050  
(2) 14,850
(3) 14400 
(4) 14700
(5) 14550

2. How many total candidates have prior experience of working in Public Sector Banks (Urban and Rural areas together) ?
(1) 37,350 
(2) 25200
(3) 30150
(4) 31950
(5) None of these

3. What is the respective ratio of the candidates who have a prior experience of working in Public Sector banks in rural areas only to the candidates who have a prior experience of working in Private sector banks in rural areas only?
(1) 4 : 3 
(2) 3 : 2
(3) 2 : 3 
(4) 3 : 4
(5) None of these

4. What is the total number of candidates who have worked in Private Sector Banks in urban areas ?
(1) 3600 
(2) 6750
(3) 12150
(4) 10800
(5) None of these

5. The candidates who have no prior experience of working in the banking industry are what per cent of the candidates who have worked in Public Sector banks in both urban and rural areas ?
(1) 60•5
(2) 63•5
(3) 62.5
(4) 64
(5) None of these

Directions—(6–10) Study the following table carefully and answer the questions given below it
The table gives the percentage of marks scored by six students in different subjects. The total marks in each subject is also given with the subject.

Students
English (100)
Hindi (100)
Science (150)
History   (60)
Maths    (150)
Geography (40)
Ankur
68
75
82
60
96
55
Jatin
88
73
85
65
88
65
Manoj
75
56
72
75
75
80
Kalpana
70
66
80
80
72
62
Charu
72
60
68
74
68
75
Dheeraj
85
70
90
70
74
70

6. What is approximate overall percentage obtained by Charu in the examination ?
(1) 78 
(2) 69
(3) 75 
(4) 71
(5) 65

7. What is the difference in the marks obtained by Dheeraj in English and the marks obtained by Manoj in the same subjects ?
(1) 12 
(2) 6.5
(3) 10 
(4) 8
(5) None of these

8. The marks obtained by Ankur in Geography are approximately what per cent of the marks as it is obtained by Kalpana in Hindi ?
(1) 45
(2) 33
(3) 50
(4) 60
(5) None of these

9. What is the overall percentage of marks obtained by Kalpana in History and Geography together ?
(1) 73•40
(2) 72•80
(3) 70•50
(4) 68•80
(5) None of these

10. What is the average marks obtained by all the students together in Science ?
(1) 79•5 
(2) 120•50
(3) 118
(4) 121
(5) None of these





ANSWERS
Solutions (1-5)

Only Urban
Only Rural
Both Urban and Rural
Total
Only public
11250
1350
10800
23400
Only private
5400
900
0
6300
Both Public and Private
6750
1800
0
8550
Total
23400
4050
10800
38250

Total Candidates = 45000
With Work Experience = 38250
Without Work Experience = 45000 – 38250 = 6750

1. (2)
Required number of candidates = 10800 + 4050 = 14850

2. (4)
Required number of candidates = 23400 + 8550 = 31950

3. (2)
Required ratio = 1350 : 900 = 3 : 2.

4. (3) Required number of candidates = 5400 + 6750 = 12150.

5. (3) Required percentage = 6750/10800 * 100 = 62.5

Solutions (6-10)

6. (2)
Total marks of Charu = 72% of 100 + 60% of 100 + 68% of 150 + 74% of 60 + 68% of 150 + 75% of 40
                                       = 72 + 60 + 102 + 44.4 + 102 + 30 = 410.4
Percentage of marks = 410.4/600 * 100 = 69 approx

7. (3)
Required difference =  (85 – 75) = 10
 
8. (2)
Required percentage =  55% OF 40/ 66% OF 100 * 100 = 72.8

9. (2)
Required percentage =  (80% of 60 +62% of 40)/ (60 + 40) * 100 = 72.8

10. (5)
Average marks of all students in science = (82 + 85 + 72 + 80 + 68 + 90)/6 * 150/100 = 119.25


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