1.A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 1/3hours to fill the tank. The leak can drain all the water of the tank in:
A.4 1/3hours
B.7 hours
C.3 9/17 hours
D.4 1/2 hours
2.A book was sold for Rs 27.50 with a profit of 10%. If it were sold for Rs. 25.75, then would have been percentage of profit and loss ?
A.2% Profit
B.3% Profit
C.2% Loss
D.3% Loss
3.How much time will it take for an amount of Rs. 900 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
A. 2 years
B. 3 years
C. 1 year
D. 4 years
4.A sphere of radius 3cm is drawn into a wire of thickness of 0.5cm. What is the length of the wire?
A.146cm
B.144cm
C.148cm
D.154cm
5.A sphere of radius 7cm is cut into two equal halves.what is the volume of each of the halves?
A.718 2/3
B.718 3/2
C.719 2/3
D.719 3/5
6.What is the compound intrest on Rs.10000 at 40% p.a. for 9 months,intrest being compounded quartely?
A. 3310
B. 3610
C. 3340
D. 3320
7. Rahul sold his bycycle after offering 10% discount.If he had sold it after offering another discount of the same amount,his selling price would have been Rs.480 find his marked prices.
A. 640
B. 600
C. 700
D. 680
8.A can do a work in 6 days more than what B takes to do the work. A worked for 7 days, then B takes the work and completed it in 10 more days.In how many days each of them can complete the work individually?
A.A can 21 days and B can 15 days
B.A can 24 days and B can 17 days
C.A can 22 days and B can 16 days
D.A can 26 days and B can 15 days
9.12 men can do a work in 15 days working 8 hours a days. In how many days can 9 men do the same work, working 10 hours a days?
A. 20
B. 18
C. 16
D. 21
10. Find value of tan6°x tan42°x tan48°x tan84°
A. 1
B. 2
C. 3
D. 0
ANSWERS AND SOLUTION:
1.(D)Explanation:
Work done by the leak in 1 hour = (1/2-3/7)=1/14
SO Leak will empty the tank in 14 hrs.
2(B)Explanation:
S.P.=(100+gain%)/100 x C.P)
So, C.P. = (100/110x25.75)
When S.P. = 25.75 then
Profit=25.75-25=Re.0.75
Profit%=0.75/25x100=3%
3(A)Explanation :
P = Rs.900
SI = Rs.81
T = ?
R = 4.5%
T= (100×SI)/PR= (100×81)/(900×4.5)=2 years
4(B)Explanation:
Since the sphere is drawn into wire,volume of the sphere is equal to volume of the wire.4/3p(3)^3= p(5/10)^2xh
=>h=144cm
5(A)
6(A)
7(B)Explanation:
Let his marked price be x
SP = MP-Discount
so 480 = x-2(10/100)x
x = 600
8(A)Explanation:
Let B take x days to do the work.
A takes (x+6) days to do the work.
Workdone by A in 7 days. 7/x+6
Workdone by B in 10 days. 10/x
So 7/x+6 + 10/x =1
(7x+10x+60)/(x+6)(x) = 1
17x + 60=x^2+6x
=>x^2 - 11x-60 = 0
=>x^2-15x + 4x-60=0
=>x(x-15)+4(x-15)=0
=>x=15
A can do the 21 days and B can do 15 day.
9(C)Explanation:
We have M1D1H1 = M2D2H2
so 12x15x8 = 9xD2x10
D2 = 16days.
10(A)
Work done by the leak in 1 hour = (1/2-3/7)=1/14
SO Leak will empty the tank in 14 hrs.
2(B)Explanation:
S.P.=(100+gain%)/100 x C.P)
So, C.P. = (100/110x25.75)
When S.P. = 25.75 then
Profit=25.75-25=Re.0.75
Profit%=0.75/25x100=3%
3(A)Explanation :
P = Rs.900
SI = Rs.81
T = ?
R = 4.5%
T= (100×SI)/PR= (100×81)/(900×4.5)=2 years
4(B)Explanation:
Since the sphere is drawn into wire,volume of the sphere is equal to volume of the wire.4/3p(3)^3= p(5/10)^2xh
=>h=144cm
5(A)
6(A)
7(B)Explanation:
Let his marked price be x
SP = MP-Discount
so 480 = x-2(10/100)x
x = 600
8(A)Explanation:
Let B take x days to do the work.
A takes (x+6) days to do the work.
Workdone by A in 7 days. 7/x+6
Workdone by B in 10 days. 10/x
So 7/x+6 + 10/x =1
(7x+10x+60)/(x+6)(x) = 1
17x + 60=x^2+6x
=>x^2 - 11x-60 = 0
=>x^2-15x + 4x-60=0
=>x(x-15)+4(x-15)=0
=>x=15
A can do the 21 days and B can do 15 day.
9(C)Explanation:
We have M1D1H1 = M2D2H2
so 12x15x8 = 9xD2x10
D2 = 16days.
10(A)
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