1. 2, 5, 9, 19, 37 ?
(a) 73
(b) 75
(c) 76
(d) 78
2. 22, 24, 28, ?, 52, 84
(a)36
(b) 38
(c)42
(d) 46
3. 1, 4, 27, 16, ?, 36, 343
(a) 25
(b) 87
(c) 120
(d) 125
4. 1/2, 3/4, 5/8, 7/16, ?
(a) 9/32
(b) 10/17
(c) 11/34
(d) 12/35
5. 1, 9, 25, 49, ?, 121
(a) 64
(b) 81
(c) 91
(d) 100
6. B, D, F, I, L, P, ?
(a)R
(b) S
(c) T
(d) U
7. U,B,I,P,W ,?
(a) D
(b)F
(c) Q
(d) U
8. Z, ?, T, ?, N, ?, H, ?, B
(a) W,Q,K,E
(b) W,R,K,E
(c) X,Q,K,E
(d) X,R,K,E
9. a , d , c , f , ?, h , g , ? , i
(a) e, j
(b) e, k
(c) f, j
(d) j, e
10. A, I, P, V, A, E, ?
(a) E
(b) F
(c) G
(d) H
Answers with Solutions
1.(b)
Clearly, we have: 2 x 2 + 1= 5, 5 x 2 -1 = 9, 9 x 2 + 1 = 19, 19 x 2 -1 = 37,
So, missing term = 37 x 2 + 1 =75.
2.(a)
The pattern is +2, +4, +8, +16
So, missing term = 28 + 8 = 36.
3.(d)
Clearly, the given the series consists of cubes of odd numbers and squares of even numbers, I. e, 13, 23, 33, 43, ….
So, missing term = 53 = 125.
4.(a)
Clearly, the numerators of the fractions in the given sequence form the series 1, 3, 5, 7, in which each term is obtained by adding 2 to the previous term.The denominators of the fractions form the series 2, 4, 8, 16, i.e. 21, 22, 23, 24.So, the numerator of the fractions will be (7 +2) i.e. 9 and the denominator will be 25 i.e. 32.
Thus, the next term is 9/32.
5.(b)
The given series consists of squares of consecutive odd numbers i.e. 12, 32, 52,72,…… So, missing term = 92 =81
6.(c)
B(+2)→D (+2)→ (+3)→ (+3)→ (+4)→P (+4)→T
7.(a)
U (+7)→B (+7)→I (+7)→P (+7)→ (+7)→D
8.(a)
Z (-6)→T (-6)→N (-6)→ (-6)→B
Z (-3)→ (-3)→T (-3)→Q (-3)→N (-3)→K (-3)→H (-3)→ (-3)→B
9.(a)
a (+3)→d (-1)→c (+3)→f (-1)→e (+3)→ (-1)→g (+3)→j (-1)→i.
10.(d)
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