1.A tyre has 2 punctures.The first puncture alone would have made the tyre flate in 9 minutes and the second alone would have done it in 6 minutes.If air leaks out a constant rate ,how long does it take both the punctures together to make in flat?
(A)1 1/2 minutes
(B)3 1/2 minutes
(C)3 3/5 minutes
(D)4 1/4 minutes
2.A cloth merchant claims to sell cloth at cost price. However, the metre scale he uses is only 96 cm long. Then what is gain%?
(A)4 1/6%
(B)5%
(C)7%
(D)9%
3.An article is sold at a loss of 10%. Had it been sold for Rs. 9 more, there would have been a gain of 12 .5%on it, then what is the cost price of the article?
(A)Rs 72
(B)Rs 60
(C)Rs 40
(D)Rs 80
4.In a journey of 160 km, a train covers the distance 120 km at a speed of 80 km/h and the remaining distance at 40 km/h. Find the average speed of the train for the whole journey.
(A)60 km/h
(B)64 km/h
(C)40 km/h
(D)45 km/h
5.The average of squares of first 11 consecutive even numbers is:
(A)184
(B)154
(C)164
(D)144
6.8 men working 9 hours a day complete a piece of work in 20 days. In how many days can 7 men working for 10 hours a day complete the same piece of work?
(A)25 days
(B)40 days
(C)21 days
(D)20 days
7.If 4 men or 6 boys can finish a piece of work in 20 days, in how many days can 6 men and 11 boys finish it?
(A)4 days
(B)6 days
(C)5 days
(D)7 days
8.A certain distance is covered by a vehicle at a certain speed. If half of this distance is covered by another vehicle in double the time, the ratio of speeds of the two vehicle is
(A)4 : 1
(B)1 : 2
(C)2 : 1
(D)1 : 4
9.Two train of equal lengths are running on parallel lines in the same directions at the rate of 92 km/h and 72 km/h respectively. The faster train passes the slower train in 54 seconds. The length of each train is
(A)500 m.
(B)180 m.
(C)150 m.
(D)240 m.
10.The simple interest on a sum of money is equal to principal and the number of years is equal to the rate percent per annum. Then find the rate.
(A)15%
(B)8%
(C)7%
(D)10%
1.(A)
2.(A)Gain % = 4/96 × 100 = 4 1/6%
3.(C)
4.(B)
5.(A)
6.(D)
7.(B)Here, x1 = 4, y1 = 6
D = 20, x2 = 6, y2 = 11
so Number of days = D(x1*y1)/(x1y2)+(y1x2)
=(20*4*6)/(4*11+6*6)=> (20*4*6)/80
= 6 days
8.(A)Let x km be covered in y hrs.
so First speed = x/y km./h
Again x/2 km is covered in 2y hrs.
so New speed = = x/2 * 1/2y = x/4y km/h
Ratio of speeds = x/y : x/4y = 4 : 1
9.(C)Speed of faster train relative to slower train
= (92 – 72) km/h = 20 km/h
= 20 × 5/18 = 50/9m/s
Distance covered in 54 seconds =(50/9*54) m = 300 m
2(length of each train) = 300m
=>length of each train = 150 m
10.(D)Let S.I. = principal = ` x
and Rate = time = y
then R = (S.I.x100)/PxT =>y = (x*100)/(x*y)
y^2 = 100
y = 10
so Rate = 10%
2.(A)Gain % = 4/96 × 100 = 4 1/6%
3.(C)
4.(B)
5.(A)
6.(D)
7.(B)Here, x1 = 4, y1 = 6
D = 20, x2 = 6, y2 = 11
so Number of days = D(x1*y1)/(x1y2)+(y1x2)
=(20*4*6)/(4*11+6*6)=> (20*4*6)/80
= 6 days
8.(A)Let x km be covered in y hrs.
so First speed = x/y km./h
Again x/2 km is covered in 2y hrs.
so New speed = = x/2 * 1/2y = x/4y km/h
Ratio of speeds = x/y : x/4y = 4 : 1
9.(C)Speed of faster train relative to slower train
= (92 – 72) km/h = 20 km/h
= 20 × 5/18 = 50/9m/s
Distance covered in 54 seconds =(50/9*54) m = 300 m
2(length of each train) = 300m
=>length of each train = 150 m
10.(D)Let S.I. = principal = ` x
and Rate = time = y
then R = (S.I.x100)/PxT =>y = (x*100)/(x*y)
y^2 = 100
y = 10
so Rate = 10%
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