1. 16, 33, 65, 131, 261, (....)
A. 523
B. 521
C. 613
D. 721
2. 10, 5, 13, 10, 16, 20, 19, (....)
A. 22
B. 40
C. 38
D. 23
3. 1, 4, 9, 16, 25, 36, 49, (....)
A.54
B.56
C.64
D.81
4. 2, 4, 12, 48, 240, (....)
A.960
B.1440
C.1920
5. 8, 7, 11, 12, 14, 17, 17, 22, (....)
A.27
B.20
C.22
D.24
6. ZA5, Y4B, XC6, W3D, _____
A.E7V
B.V2E
C.VE5
D.VE7
7. QPO, NML, KJI, _____, EDC
A.HGF
B.CAB
C.JKL
D.GHI
8. JAK, KBL, LCM, MDN, _____
A.OEP
B.NEO
C.MEN
D.PFQ
9. BCB, DED, FGF, HIH, ___
A.JKJ
B.HJH
C.IJI
D.JHJ
10. P5QR, P4QS, P3QT, _____, P1QV
A.PQW
B.PQV2
C.P2QU
D.PQ3U
Answers:-
1.A
Each number is twice the preceding one with 1 added or subtracted alternatively.
So, the next number is (2 x 261 + 1) = 523.
2.B
There are two series (10, 13, 16, 19) and (5, 10, 20, 40), one increasing by 3 and the other multiplied by 2.
3.C
So, the next number is 8^2 = 64.
4.B
So, the correct next number is 1440.
5.B
There are two series (8, 11, 14, 17, 20) and (7, 12, 17, 22) increasing by 3 and 5 respectively.
6.D
There are three series to look for here. The first letters are alphabetical in reverse: Z, Y, X, W, V. The second letters are in alphabetical order, beginning with A. The number series is as follows: 5, 4, 6, 3, 7.
7.A
This series consists of letters in a reverse alphabetical order.
8.B
This is an alternating series in alphabetical order. The middle letters follow the order ABCDE. The first and third letters are alphabetical beginning with J. The third letter is repeated as a first letter in each subsequent three-letter segment.
9.A
This series consists of a simple alphabetical order with the first two letters of all segments: B, C, D, E, F, G, H, I, J, K. The third letter of each segment is a repetition of the first letter.
10.C
The first two letters, PQ, are static. The third letter is in alphabetical order, beginning with R. The number series is in descending order beginning with 5
A. 523
B. 521
C. 613
D. 721
2. 10, 5, 13, 10, 16, 20, 19, (....)
A. 22
B. 40
C. 38
D. 23
3. 1, 4, 9, 16, 25, 36, 49, (....)
A.54
B.56
C.64
D.81
4. 2, 4, 12, 48, 240, (....)
A.960
B.1440
C.1920
5. 8, 7, 11, 12, 14, 17, 17, 22, (....)
A.27
B.20
C.22
D.24
6. ZA5, Y4B, XC6, W3D, _____
A.E7V
B.V2E
C.VE5
D.VE7
7. QPO, NML, KJI, _____, EDC
A.HGF
B.CAB
C.JKL
D.GHI
8. JAK, KBL, LCM, MDN, _____
A.OEP
B.NEO
C.MEN
D.PFQ
9. BCB, DED, FGF, HIH, ___
A.JKJ
B.HJH
C.IJI
D.JHJ
10. P5QR, P4QS, P3QT, _____, P1QV
A.PQW
B.PQV2
C.P2QU
D.PQ3U
Answers:-
1.A
Each number is twice the preceding one with 1 added or subtracted alternatively.
So, the next number is (2 x 261 + 1) = 523.
2.B
There are two series (10, 13, 16, 19) and (5, 10, 20, 40), one increasing by 3 and the other multiplied by 2.
3.C
So, the next number is 8^2 = 64.
4.B
So, the correct next number is 1440.
5.B
There are two series (8, 11, 14, 17, 20) and (7, 12, 17, 22) increasing by 3 and 5 respectively.
6.D
There are three series to look for here. The first letters are alphabetical in reverse: Z, Y, X, W, V. The second letters are in alphabetical order, beginning with A. The number series is as follows: 5, 4, 6, 3, 7.
7.A
This series consists of letters in a reverse alphabetical order.
8.B
This is an alternating series in alphabetical order. The middle letters follow the order ABCDE. The first and third letters are alphabetical beginning with J. The third letter is repeated as a first letter in each subsequent three-letter segment.
9.A
This series consists of a simple alphabetical order with the first two letters of all segments: B, C, D, E, F, G, H, I, J, K. The third letter of each segment is a repetition of the first letter.
10.C
The first two letters, PQ, are static. The third letter is in alphabetical order, beginning with R. The number series is in descending order beginning with 5
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