Directions (1-5): Following bar-graph shows the percentage growth of population of six cities A, B, C, D, E and F during 1990 to 2000 and 2000-2010.
1. If population of City D in 1990 is 40 lakhs, what is its population in 2010?
(1) 91 lakhs
(2) 75 lakhs
(3) 60 lakhs
(4) 68 lakhs
(5) None of these
2. Population of City A and City B in 1990 is in ratio of 4 : 3 and population of City A in 1990 is 32 lakhs so what is the population of City B in 2010?
(1) 36 lakhs
(2) 34.5 lakhs
(3) 32 lakhs
(4) 30 lakhs
(5) None of these
3. If population of City E is 62 lakhs in 2010 then what was its population in 1990?
(1) 48 lakhs
(2) 45 lakhs
(3) 44 lakhs
(4) 40 lakhs
(5) None of these
4. If population of City C in 1990 and population of City F in 2000 is in ratio of 6 : 7 and if population of City C is 48 lakhs in 1990 then what is the sum of population of City C in 2000 and population of City F in 2010?
(1) 132.5 lakhs
(2) 137.6 lakhs
(3) 139.4 lakhs
(4) 144 lakhs
(5) None of these
5. Population of City E in 2010 is how much percentage more than that its population in 1990?
(1) 45%
(2) 50%
(3) 55%
(4) 60%
(5) None of these
Directions (6-10): Each question below is followed by two statements I and II. You are to determine whether the data given in the statement is sufficient to answer the question. You should use the data and your knowledge of Mathematics to choose between the possible answers.
Give answer-
(1) If the question can be answered by using statement I alone but can not be answered by statement II alone.
(2) If the question can be answered by using statement II alone but can not be answered by statement I alone.
(3) If both statements I and II together are required to answer the question.
(4) If the answer can be derived by using any of the two statements alone.
(5) If the answer cannot be derive even using both the statements.
6. How many days will Ram take to make 150 toys?
I. Shyam takes 10 days to make 100 toys.
II. Ram and Shyam together make 150 toys in 6 days.
7. What is the present age of A and B?
I. Ratio of their present ages is 3 : 1.
II. Ratio of their ages 10 years before was 5 : 1.
8. What is the area of rectangle?
I. Perimeter is 20 meter.
II. Sum of two adjacent sides is 10 meters.
9. How many letters can 12 typists complete in one day?
I. A working day consists of 8 hours?
II. 5 typists can type 200 letters in 2 days.
10. If a man wants to cover a square room with a carpet, how much will it cost?
I. If the service charge is Rs 15 and each square yard cost is Rs 20.
II. If the room were ½ as large in area, it would cost Rs 150 less.
Answers :
1. (4); Population in 2010 = 40 * 136/100 * 125/100 = 68 lakhs
2. (2) ;
Population of A in 1990 = 32 lakhs
Population of B in 1990 = 24 lakhs
Population of B in 2010 = 24 * 125/100 * 115/100 = 34.5 lakhs
3. (4)
4. (2)
5. (3)
Solutions (6-10)
6. (3) ;
Both statements are required.
From statement I:
Shyam makes 100/10 = 10 toys in one day.
From statement II
Shyam and Ram make 150/6 toys in 1 day ie 25 toys in 1 day.
ie Ram alone makes 25 – 10 = 15 toys per day.
For 150 toys he will take 150/10 = 10 days.
7. (3);
Both statements are required.
Let their age be x and y.
From statement I:
x/y = 3/1
x = 3y ...(i)
From statement II:
(x - 10)/ (y - 10) = 5/1
x – 10 = 5y – 50
x – 5y = –40 ...(ii)
From equations (i) and (ii),
x = 60 years
y = 20 years
8. 5;
Using Statement I:
2(L + B) = 20
L + B = 10
Using Statement II:
L + B = 10
So, even by using both the statements together we cannot find the area of the rectangle.
9. (2) ;
Using Statement II:
In 2 days 5 typists type 200 letters.
In 1 day 5 typists type 100 letters.
In 1 day 1 typist types 20 letters.
In 1 day 12 typists type 240 letters.
10. (3) ;
1. If population of City D in 1990 is 40 lakhs, what is its population in 2010?
(1) 91 lakhs
(2) 75 lakhs
(3) 60 lakhs
(4) 68 lakhs
(5) None of these
2. Population of City A and City B in 1990 is in ratio of 4 : 3 and population of City A in 1990 is 32 lakhs so what is the population of City B in 2010?
(1) 36 lakhs
(2) 34.5 lakhs
(3) 32 lakhs
(4) 30 lakhs
(5) None of these
3. If population of City E is 62 lakhs in 2010 then what was its population in 1990?
(1) 48 lakhs
(2) 45 lakhs
(3) 44 lakhs
(4) 40 lakhs
(5) None of these
4. If population of City C in 1990 and population of City F in 2000 is in ratio of 6 : 7 and if population of City C is 48 lakhs in 1990 then what is the sum of population of City C in 2000 and population of City F in 2010?
(1) 132.5 lakhs
(2) 137.6 lakhs
(3) 139.4 lakhs
(4) 144 lakhs
(5) None of these
5. Population of City E in 2010 is how much percentage more than that its population in 1990?
(1) 45%
(2) 50%
(3) 55%
(4) 60%
(5) None of these
Directions (6-10): Each question below is followed by two statements I and II. You are to determine whether the data given in the statement is sufficient to answer the question. You should use the data and your knowledge of Mathematics to choose between the possible answers.
Give answer-
(1) If the question can be answered by using statement I alone but can not be answered by statement II alone.
(2) If the question can be answered by using statement II alone but can not be answered by statement I alone.
(3) If both statements I and II together are required to answer the question.
(4) If the answer can be derived by using any of the two statements alone.
(5) If the answer cannot be derive even using both the statements.
6. How many days will Ram take to make 150 toys?
I. Shyam takes 10 days to make 100 toys.
II. Ram and Shyam together make 150 toys in 6 days.
7. What is the present age of A and B?
I. Ratio of their present ages is 3 : 1.
II. Ratio of their ages 10 years before was 5 : 1.
8. What is the area of rectangle?
I. Perimeter is 20 meter.
II. Sum of two adjacent sides is 10 meters.
9. How many letters can 12 typists complete in one day?
I. A working day consists of 8 hours?
II. 5 typists can type 200 letters in 2 days.
10. If a man wants to cover a square room with a carpet, how much will it cost?
I. If the service charge is Rs 15 and each square yard cost is Rs 20.
II. If the room were ½ as large in area, it would cost Rs 150 less.
Answers :
1. (4); Population in 2010 = 40 * 136/100 * 125/100 = 68 lakhs
2. (2) ;
Population of A in 1990 = 32 lakhs
Population of B in 1990 = 24 lakhs
Population of B in 2010 = 24 * 125/100 * 115/100 = 34.5 lakhs
3. (4)
4. (2)
5. (3)
Solutions (6-10)
6. (3) ;
Both statements are required.
From statement I:
Shyam makes 100/10 = 10 toys in one day.
From statement II
Shyam and Ram make 150/6 toys in 1 day ie 25 toys in 1 day.
ie Ram alone makes 25 – 10 = 15 toys per day.
For 150 toys he will take 150/10 = 10 days.
7. (3);
Both statements are required.
Let their age be x and y.
From statement I:
x/y = 3/1
x = 3y ...(i)
From statement II:
(x - 10)/ (y - 10) = 5/1
x – 10 = 5y – 50
x – 5y = –40 ...(ii)
From equations (i) and (ii),
x = 60 years
y = 20 years
8. 5;
Using Statement I:
2(L + B) = 20
L + B = 10
Using Statement II:
L + B = 10
So, even by using both the statements together we cannot find the area of the rectangle.
9. (2) ;
Using Statement II:
In 2 days 5 typists type 200 letters.
In 1 day 5 typists type 100 letters.
In 1 day 1 typist types 20 letters.
In 1 day 12 typists type 240 letters.
10. (3) ;
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