1.A fan in a shop is offered at a discount of 10%. It is sold during clearance sale at 6% discount over the already discounted price at Rs. 846/- . The original marked price of the fan is:
(a) Rs. 850/-
(b) Rs. 896/-
(c) Rs. 900/-
(d) Rs. 946/-
(e)Rs. 1000/-
2.A trader allows a trade discount of 20% and a cash discount of 25/4% on the marked price of the goods and gets a net gain 20% of the cost. By how much above the cost should the goods be marked for sale?
(a) 60%
(b) 70%
(c) 40%
(d) 50%
(e)none of these
3.A discount series of 10%, 20% and 40% is equal to a single discount of :
(a) 70%
(b) 43.20%
(c) 56.80%
(d) 50%
(e)none of these
4.Tarun bought a T.V. with 20% discount on the labeled price. Had he bought it with 25% discount, he would have saved Rs. 500/-. At what price did he buy the T.V.?
(a) Rs. 8, 000/-
(b) Rs. 7, 400/-
(c) Rs. 7, 500/-
(d) Rs. 8, 500/-
(e)none of these
5.Two vessels contain milk and water in the ratio 3 : 2 and 7 : 3. Find the ratio in which the contents of the two vessels have to be mixed to get a new mixture in which he ratio of milk and water is 2:1.
(a) 4:1
(b) 1:4
(c) 2:1
(d) 1:2
(e)none of these
6.The students in three classes are in the ratio 4 : 6 : 9. If 12 students are increased in each class, the ratio changes to 7 : 9 : 12. Then the total number of students in the three classes before the increase is:
(a)100
(b)114
(c)95
(d)76
(e)none of these
7.Of the adult population in a certain city, 45% of men and 25% of women are married. Assuming that no man marries more than one woman, and vice versa, the percentage of total population of adults who are married, is:
(a) 31.1
(b) 30
(c) 33.33
(d) 32.14
(e)none of these
8.A garrison is provided with ration for 72 soldiers to last for 54 days. Find how long would the same amount of food last for 90 soldiers, if he individual ration is reduced by 10?
(a) 54 days
(b) 126 days
(c) 48 days
(d) 72 days
(e)none of these
9.In an examination paper of five question, 5% of the conditions answered all of them and 5% answered none. Of the rest, 25% candidates answered only one question and 20% answered 4 questions. If 396 candidates answered either 2 questions or 3 questions, the number of candidates that appeared for the examination was:
(a) 850
(b) 900
(c) 800
(d) 1,000
(e)none of these
10. In a test, A scored 10% more than B and B scored 5% more than C. If C scored 300 marks out of 400, then A’s marks are:
(a) 350
(b) 360
(c) 310
(d) 325
(e)none of these
Answers with Explantion
1.(e) SP before 6% discount = 846 * 100/94
So, original MP = 846 x 100/94 * 100/90 = 1000
2.(a) Let CP = 100
Profit = 20%
S.P = 120
M.P = 120 * 100/80 * 100/(100-25/4) = 160
3.(c) Single discount from 1st two discount
= 10 + 20 – (10*20/100) = 28
So, final discount = 28 + 40 – (28*40/100)
= 56.8%
4.(a)Given 5% = 500
1% = 100
100% = 10000
Required price = 10000 * 80/100 = 8000
5.(d)
1 : 2
6.(d) Since 3 = 12
1 = 4
(4+6+3) = 19 * 4 = 76
7.(d) Let no 9 men = x & total population be 100
Total women = (100-x)
Married man = 45x /100 … (i)
& married women = 25/100 (100-x) … (ii)
From (i) & (ii)
x = 500/14
So, married man = 225 /14
Married woman = 225/14
Total married population = men + women = 450/14
Required % = (450/14)/100 *100 = 450/14% = 32.14%
8.(c) Let required day = x
54 x 72 = 90 * x * 90/100
x = 48
9. (c) Let total no of candidates = 1000
So, 1000 – (50 +50+900*1/4+900*1/5) = 396
495 = 396
1000 = 396/495 * 1000 = 800
10.(b) Given, C's marks= 300
C's % marks = 300*100/400=75%
B 's% marks = 80%
A 's% marks =90%
A 's marks = 90% of 400
= 360
(a) Rs. 850/-
(b) Rs. 896/-
(c) Rs. 900/-
(d) Rs. 946/-
(e)Rs. 1000/-
(a) 60%
(b) 70%
(c) 40%
(d) 50%
(e)none of these
3.A discount series of 10%, 20% and 40% is equal to a single discount of :
(a) 70%
(b) 43.20%
(c) 56.80%
(d) 50%
(e)none of these
4.Tarun bought a T.V. with 20% discount on the labeled price. Had he bought it with 25% discount, he would have saved Rs. 500/-. At what price did he buy the T.V.?
(a) Rs. 8, 000/-
(b) Rs. 7, 400/-
(c) Rs. 7, 500/-
(d) Rs. 8, 500/-
(e)none of these
5.Two vessels contain milk and water in the ratio 3 : 2 and 7 : 3. Find the ratio in which the contents of the two vessels have to be mixed to get a new mixture in which he ratio of milk and water is 2:1.
(a) 4:1
(b) 1:4
(c) 2:1
(d) 1:2
(e)none of these
6.The students in three classes are in the ratio 4 : 6 : 9. If 12 students are increased in each class, the ratio changes to 7 : 9 : 12. Then the total number of students in the three classes before the increase is:
(a)100
(b)114
(c)95
(d)76
(e)none of these
7.Of the adult population in a certain city, 45% of men and 25% of women are married. Assuming that no man marries more than one woman, and vice versa, the percentage of total population of adults who are married, is:
(a) 31.1
(b) 30
(c) 33.33
(d) 32.14
(e)none of these
8.A garrison is provided with ration for 72 soldiers to last for 54 days. Find how long would the same amount of food last for 90 soldiers, if he individual ration is reduced by 10?
(a) 54 days
(b) 126 days
(c) 48 days
(d) 72 days
(e)none of these
9.In an examination paper of five question, 5% of the conditions answered all of them and 5% answered none. Of the rest, 25% candidates answered only one question and 20% answered 4 questions. If 396 candidates answered either 2 questions or 3 questions, the number of candidates that appeared for the examination was:
(a) 850
(b) 900
(c) 800
(d) 1,000
(e)none of these
10. In a test, A scored 10% more than B and B scored 5% more than C. If C scored 300 marks out of 400, then A’s marks are:
(a) 350
(b) 360
(c) 310
(d) 325
(e)none of these
Answers with Explantion
1.(e) SP before 6% discount = 846 * 100/94
So, original MP = 846 x 100/94 * 100/90 = 1000
2.(a) Let CP = 100
Profit = 20%
S.P = 120
M.P = 120 * 100/80 * 100/(100-25/4) = 160
3.(c) Single discount from 1st two discount
= 10 + 20 – (10*20/100) = 28
So, final discount = 28 + 40 – (28*40/100)
= 56.8%
4.(a)Given 5% = 500
1% = 100
100% = 10000
Required price = 10000 * 80/100 = 8000
5.(d)
1 : 2
6.(d) Since 3 = 12
1 = 4
(4+6+3) = 19 * 4 = 76
7.(d) Let no 9 men = x & total population be 100
Total women = (100-x)
Married man = 45x /100 … (i)
& married women = 25/100 (100-x) … (ii)
From (i) & (ii)
x = 500/14
So, married man = 225 /14
Married woman = 225/14
Total married population = men + women = 450/14
Required % = (450/14)/100 *100 = 450/14% = 32.14%
8.(c) Let required day = x
54 x 72 = 90 * x * 90/100
x = 48
9. (c) Let total no of candidates = 1000
So, 1000 – (50 +50+900*1/4+900*1/5) = 396
495 = 396
1000 = 396/495 * 1000 = 800
10.(b) Given, C's marks= 300
C's % marks = 300*100/400=75%
B 's% marks = 80%
A 's% marks =90%
A 's marks = 90% of 400
= 360
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