Missing Number In Figure
SOLUTIONS
1. (3) Here we get the lowermost term by adding the two up- permost terms of the square and doubling it .
As, (1 + 2) × 2 = 6
(3 + 2) × 2 = 10,
Similarly,
(3 + 4) × 2 = 14.
2. (1) Here the number series is as follows-
22 –3 = 1
12 – 2 = –1
32 – 4 = 5.
3. (2) 5× 6 + 3 × 3 = 39 and,
7 × 5 + 4 × 4 = 51
5 × 5 + 3 × 4 = 37
4. (3) 9 + 7 – 5 = 11 and,
6 + 4 – 8 = 2
8 + ? – 4 = 7
5. (3) 4 + 9 + 17 + 6 = 36
20 + 5 + 8 + 9 = 42
7 + 23 + 9 + 9 = 48
9 + 4 + 19 + ? = 40
® ? = 40 – 32 = 8
6. (3) 13 × 17 = 221
12 × 19 = 228
13 × 18 = 234
7. (2) 3 × 3 = 9, 9 × 3 = 27, 27 × 3 = 81
6 × 3 = 18, 18 × 3 = 54, 54 × 3 = 162
7 × 3 = 21, 21 × 3 = 63, 63 × 3 = 189
8. (3) 5 + 0 = 5, 5 + 3
= 8, 8 + 3 = 11
7 – 3 = 4, 3 + 5 = 8, 8 – 2 = 6
3 + 6 = 9 and 6 + 4 = 10
1 + 0 = 0 = 1 and 0
9. (2) 1+ 2 + 4 + 3 = 10;
10 × 5 = 50
3 + 4 + 5 + 2 = 14;
14 × 5 = 70
7 + 4 + 9 + 3 = 23;
10. (1) (3)2 + (2)2 + (1)2
= 9 + 4 + 1 = 14
(4)2 + (3)2 + (2)2
= 16 + 9 + 4 = 29
Similarly,
(5)2 + (4)2 + (3)2
= 25 +16 + 9 = 50
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