1. Mohan bought a SONY cyber shot with 20% discount on list price. If he bought it with 24% discount, he would have saved Rs. 800. At what price he did buy?
(a) Rs. 20000
(b) Rs. 16000
(c) Rs. 12000
(d) Rs. 10000
2. A shopkeeper bought pens at the rate of 7 for Rs. 10 and sold them at a profit of 40%. How many pens would customer get for Rs. 14?
(a) 7
(b) 10
(c) 9
(d) 11
3. Two solutions of 90% and 97% purity are mixed, resulting in 21 L of mixture of 94% purity, The quantity of the second solution in the resulting mixture, in litre, is
(a) 16
(b) 10
(c) 14
(d) 12
4.A dishonest shopkeeper professes to sell goods at his cost price, but uses a false weight, thereby gaining 6(18/47)%. How much weight he uses for 1 kg?
(a) 950 gm.
(b) 940 gm.
(c) 965 gm.
(d) None
5.A candidate needs 850 marks to pass in an exam. If a candidate A gets 800 and fails by 5%, then full marks in the examination is
(a) 1600
(b) 1700
(c) 1000
(d) 1200
6. Two numbers are less than the third number by 50% and 55% respectively. By how much percent is the second number less than the first number?
(a) 10
(b) 9(1/11)
(c) 11(1/9)
(d) None
7. Ram’s weight is 140% of Shyam’s weight. Anil’s weight is 90% of Gaurav’s weight. Gaurav is twice as much as Shyam's weight. If Ram’s weight is b% of Anils weight, then b is
(a) 80
(b) 58 (1/5)
(c) 77 (7/9)
(d) 61 (3/7)
8. If 15a + 15b = 108, then the average of a and b is
(a) 3 (1/2)
(b) 3 (3/5)
(c) 7 (1/5)
(d) Cannot be determined
9.In a mixture of milk and water, the proportion of water by weight was 80%. If in 80%. If in 80 gm. Of mixture 16 gm water was added, then percentage of water will be
(a) 100%
(b) 75%
(c) 66 (2/3)%
(d) 83 (1/3)%
10.Twelve percent of Kaushal’s monthly salary is equal to sixteen percent of Nandini’s monthly salary. Suresh’s monthly salary is half that of Nandini’s monthly salary. If Suresh’s annual salary is Rs. 1.08 lacs. What is Kaushal’s monthly salary?
(a) Rs. 20000
(b) Rs. 18000
(c) Rs. 26000
(d) Rs. 24000
Answers and Solution:
1. (b)
Difference of (24-20) = 4% of list price is Rs. 800
=> List price = 800/4%
So cost price = 80% of list price = 80*800/4 = 16,000
2. (a)
Cost price of 1 pen = 10/7,sale price of 1 pen = (1.4*10)/7 = Rs.2
No. of pens = 14/2 = 7
3. (d)
4. (b)
Using (100+G)/(100+x) = true weight/false weight so cp = sp
so x = 0, put G = 300/47
(100+300/47)/(100+0) = 1/false weight
so false weight = 940 gm
5. (c)
5% of full = 850 - 800 => full = 50/5*100 = 1000
6. (a)
7. (c)
8. (b)
9. (d)
80 gm mixture has 80% of 80 = 64 gm water and 16 gm milk
After adding 16 gm water , new % of water = (64+16)/(80+16)*100 = 83(1/3)
10. (d)
1. (b)
Difference of (24-20) = 4% of list price is Rs. 800
=> List price = 800/4%
So cost price = 80% of list price = 80*800/4 = 16,000
2. (a)
Cost price of 1 pen = 10/7,sale price of 1 pen = (1.4*10)/7 = Rs.2
No. of pens = 14/2 = 7
3. (d)
4. (b)
Using (100+G)/(100+x) = true weight/false weight so cp = sp
so x = 0, put G = 300/47
(100+300/47)/(100+0) = 1/false weight
so false weight = 940 gm
5. (c)
5% of full = 850 - 800 => full = 50/5*100 = 1000
6. (a)
7. (c)
8. (b)
9. (d)
80 gm mixture has 80% of 80 = 64 gm water and 16 gm milk
After adding 16 gm water , new % of water = (64+16)/(80+16)*100 = 83(1/3)
10. (d)
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