1.In the solution of the multiplication question given below.'a' is s digit.
a 2
× 7 a
=6396
The value of 'a' is
(1) 3
(2) 8
(3) 6
(4) 4
2. Lengths of the perpendiculars from a point in the interior of an equilateral triangle on its sides are 3 cm. 4 cm and 5 cm. Area of the triangle is
(1) 48 √3 cm^2
(2) 54 √3 cm^2
(3) 72 √3 cm^2
(4) 80 √3 cm^2
3. A man, a woman and a boy can complete a work in 20 days. 30 days and 60 days respectively. How many boys must assist 2 men and 8 women so as to complete the work in 2 days?
(1) 8
(2) 12
(3) 4
(4) 6
4. The measures (in cm) of sides of a right angled trinagle are given by consecutive integers. Its area (in cm^2) is
(1) 9
(2) 8
(3) 5
(4) 6
5. The average age of a husband and a wife was 27 years when they married 4 years ago. The average age of the husband, the wife and a new-born child is 21 years now. The present age of the build is
(1) 4 years
(2) 3 years
(3) 2 years
(4) 1 year
6. A reduction of 25% in the price of sugar enbles a man to buy 7 1/2 kg more sugar for Rs. 360. The original price per kg of sugar was.
(1) Rs. 16
(2) Rs. 18
(3) Rs. 20
(4) Rs. 25
7. A man buys some articles at Rs. P per dozen and sells them at Rs. P/8 per piece. His profit per cent is
(1) 30
(2) 40
(3) 50
(4) 60
8. A train with a uniform speed, crosses a platform, 162 metres long, in 18 seconds and another platform, 120 metres long, in 15 seconds. The speed of the train is
(1) 14 km/hr
(2) 42 km/hr
(3) 50.4 km/hr
(4) 67.2 km/hr
9. The number of boys and girls in a college are in the ratio of 3 : 2. If 20% of the boys and 25% of the girls are adults, the percentage of students, who are not adults, is
(1) 58
(2) 66 2/3
(3) 78
(4) 83 1/3
10. What sum of money at compound interest will amount to Rs. 650 at the end of one year and Rs. 676 at the end of 2 years?
(1) Rs. 520
(2) Rs. 572
(3) Rs. 600
(4) Rs. 625
SOLUTION
1. (2)
2. (1)
3. (3) Part of work done by 2 men and 2 women in 2 days.
= 2(2/20 + 8/30)
= 2(1/10 + 8/20) = 2((3+8)/30)
= 22/30 = 11/15
Remaining work = 1 - 11/15 = 4/15
work done by 1 boy in 2 days
= 2/60 = 1/30
4. (4) 3^2 + 4^2 = 5^2
Base = 3 cm
perpedicular = 4 cm
Area of the right angled triangle
= 1/2 * base * height
= 1/2 * 3 * 4 = 6 sq. cm.
5. (4) Sum of the present ages of husband and wife
= 2 * 27 + 8 = 62 years
Sum of the present ages of husband, wife and child
= 21 * 3 = 63 years
so present age of the child = 63 - 62 = 1 year
6. (1) Let the original price of sugar = Rs. x/kg
so New price of sugar
= x * 75/100 = Rs. 3x/4
According to the question.
360/(3x/4)- 360/x= 15/2
=480/x - 360/x=15/2
=120/x=15/2
x= (120 ×2)/15=16
7.(3) CP of each article
= Rs. P/12 and SP = Rs. P/8
Gain = P/8 - P/12 = (3P - 2P)/24 = P/24
so Gain per cent = P/(24/(P/12)) ×100=50%
8. (3) Let the Length of the train be x metre.
(x + 162)/18 = (x + 120)/15
Speed of the train
= (x + 162)/6 = (x + 120)/5
= 6x + 720 = 5x + 810
x = 810 - 720 = 90
Speed of the train
= (90 + 162)/18 m/sec
= 252/18 * 18/5 kmph = 50.4 kmph
9. (3)
10.(4)
SOLUTION
1. (2)
2. (1)
3. (3) Part of work done by 2 men and 2 women in 2 days.
= 2(2/20 + 8/30)
= 2(1/10 + 8/20) = 2((3+8)/30)
= 22/30 = 11/15
Remaining work = 1 - 11/15 = 4/15
work done by 1 boy in 2 days
= 2/60 = 1/30
4. (4) 3^2 + 4^2 = 5^2
Base = 3 cm
perpedicular = 4 cm
Area of the right angled triangle
= 1/2 * base * height
= 1/2 * 3 * 4 = 6 sq. cm.
5. (4) Sum of the present ages of husband and wife
= 2 * 27 + 8 = 62 years
Sum of the present ages of husband, wife and child
= 21 * 3 = 63 years
so present age of the child = 63 - 62 = 1 year
6. (1) Let the original price of sugar = Rs. x/kg
so New price of sugar
= x * 75/100 = Rs. 3x/4
According to the question.
360/(3x/4)- 360/x= 15/2
=480/x - 360/x=15/2
=120/x=15/2
x= (120 ×2)/15=16
7.(3) CP of each article
= Rs. P/12 and SP = Rs. P/8
Gain = P/8 - P/12 = (3P - 2P)/24 = P/24
so Gain per cent = P/(24/(P/12)) ×100=50%
8. (3) Let the Length of the train be x metre.
(x + 162)/18 = (x + 120)/15
Speed of the train
= (x + 162)/6 = (x + 120)/5
= 6x + 720 = 5x + 810
x = 810 - 720 = 90
Speed of the train
= (90 + 162)/18 m/sec
= 252/18 * 18/5 kmph = 50.4 kmph
9. (3)
10.(4)
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