Quant Quiz

1. A's salary is 25% more than B's salary. B's salary is how much percent of A's salary?
(1) 80%
(2) 75%
(3) 85%
(4) 90%
(5) Cannot be determined


2. The single discount, which is equivalent to successive discounts of 40% and 15% is
(1) 61
(2) 50
(3) 65
(4) 49
(5) None of these

3. The difference between the circumference and the radius of a circle is 74 cm. The diameter of the circle is
(1) 14 cm
(2) 28 cm
(3) 37 cm
(4) 74 cm
(5) 54 cm

4. The LCM of two numbers is 180 and their HCF is 15. If one of the numbers is 60, the other number should be
(1) 45
(2) 30
(3) 90
(4) 15
(5) Data inadequate

5. The average of seven results is 15; the average of first three is 13, and that of the last three is 17. The fourth result is
(1) 16
(2) 15
(3) 14
(4) 13
(5) 18

6. A man walking at the speed of 2 kmph crosses a square field diagonally in 3 minutes. The area of the field is
(1) 20000 sq m
(2) 10000 sq m
(3) 9000 sq m
(4) 5000 sq m
(5) Cannot be determined

7. A, B and C are partners and make a profit of Rs. 10500 which is distributed among them in the ratio 6:5:4. The difference of the amounts A and C received is
(1) Rs. 1600
(2) Rs. 1400
(3) Rs. 1200
(4) Rs. 1800
(5) None of these

8. Three cars travelled distances in the ratio 1 : 2 : 3. If the ratio of the time of travel is 3 : 2 : 1. Then the ratio of their speeds is
(1) 3:9:1
(2) 1:3:9
(3) 1:2:4
(4) 4:3:2
(5) None of these

9. The ratio two numbers is 3 : 4. If each number is in increased by 6. The ratio becomes 4:5. The difference between number is
(1) 1
(2) 3
(3) 6
(4) 8
(5) None of these

10. A road of 10 km will be constructed in 100 days. So 140 workers were employed. But after 8O days it was found that only 7 km road is completed. Now how many more needed to finish the work in the specified time?
(1) 240
(2) 40
(3) 60
(4) 50
(5) None of these



ANSWERS
1. (1)
Required percentage = (100/(100 + 25) * 100 = 80%

2. (4)
Equivalent discount = 40 + 15

3. (2)
2πr – r = 74
r = 14 cm. So diameter = 28 cm

4. (1)
Other number = (15 * 180)/60 = 45

5. (2)
Fourth result = 7 * 15 – 3 * 13 – 3 * 17 = 15

6. (5)
Distance covered by man in 3 mins = 2 * 3/60 = 1/10 km = 100 m
Diagonal of square = 100 m
Area of square =1/2 of (100)^2 = 5000 sq m

7. (2)
Required difference = 6/15 of 10500 – 4/15 of 10500 = 1400

8. (2)
Speed = Distance/Time. SO
Required ratio = 1/3 : 1/1 : 3/1 = 1:3:9

9. (3)
Let the numbers be 3x and 4x respectively. Now
(3x + 6)/(4x + 6) = 4/5
x = 6
Difference = 4x – 3x = x = 6

10. (5)
Let the number of additional workers be x. Then
(140 * 80)/7 = {(140 + x) * (100 - 80)}/3
x = 100