Directions (1–6): What will come in the place of the question mark (?) in the following number series?
1. 1108, 1117, 1142, 1191, ?, 1393
(1) 1312
(2) 1300
(3) 1272
(4) 1204
(5) None of these
2. 25, 30, 70, 260, 1280, ?
(1) 6400
(2) 7680
(3) 6380
(4) 7660
(5) None of these
3. 8484, 4248, 2112, 1074, 513, ?
(1) 201
(2) 280.5
(3) 256.5
(4) 171
(5) None of these
4. 154, 162, 226, ?, 954, 1954
(1) 242
(2) 554
(3) 442
(4) 642
(5) None of these
5. 1, 3, 24, 360, 8640, 302400, ?
(1) 14525100
(2) 154152000
(3)14515200
(4)15425100
(5) None of these
6. 5, 9, 17, 33, ?
(1) 63
(2) 65
(3)127
(4) 95
(5) 73
7. In an examination a minimum marks is to be scored in each of the 8 subjects for passing. In how many ways a student can fail?
(1) 127
(2) 63
(3) 255
(4) 256
(5) None of these
8. A man can row at 10 kmph in still water. If the river flows at 3 kmph and, it takes 12 hours more in upstream than to go downstream for the same distance. How far is the place?
(1) 160 km
(2) 164 km
(3) 170 km
(4) 175 km
(5) None of these
9. A alone would take 6 hours more to complete the job than if both A and B would work together. When B worked alone he took 1.5 hours more to complete the job and A and B worked together. How much time they will take if they work together?
(1) 3 hours
(2) 4 hours
(3) 4.5 hours
(4) 5 hours
(5) None of these
10. From a pack of 52 cards, 2 cards are drawn randomly. What is probability that it has one King and one Jack?
(1) 7/663
(2) 8/663
(3) 11/663
(4) 13/663
(5) None of these
11. A two-digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is
(1) 18
(2) 24
(3) 81
(4) 42
(5) None of these
ANSWERS
7. (3) ;
The students can fail in 1, 2, 3, 4, 5, 6, 7, 8 subjects.
So the number of ways he can fail is
8C1 + 8C2 + 8C3 + 8C4 + 8C5 + 8C6 + 8C7 + 8C8
= 8 + 28 + 56 + 70+56 + 28 + 8 + 1 = 255
8. (5); Let distance be = x
x/(10 - 3) - x/(10 + 3) = 12
x/7 - x/13 = 12
(13x - 7x)/ 91 = 12
6x/91 = 12
x = 182 km
9. (1)
10. (2) ;
n (S) = 52C2 = 51 × 26
n (E) = 4C1 × 4C1 = 4 × 4
p (E) = 16/51*26 = 8/663
11. (4)
1. 1108, 1117, 1142, 1191, ?, 1393
(1) 1312
(2) 1300
(3) 1272
(4) 1204
(5) None of these
2. 25, 30, 70, 260, 1280, ?
(1) 6400
(2) 7680
(3) 6380
(4) 7660
(5) None of these
3. 8484, 4248, 2112, 1074, 513, ?
(1) 201
(2) 280.5
(3) 256.5
(4) 171
(5) None of these
4. 154, 162, 226, ?, 954, 1954
(1) 242
(2) 554
(3) 442
(4) 642
(5) None of these
5. 1, 3, 24, 360, 8640, 302400, ?
(1) 14525100
(2) 154152000
(3)14515200
(4)15425100
(5) None of these
6. 5, 9, 17, 33, ?
(1) 63
(2) 65
(3)127
(4) 95
(5) 73
7. In an examination a minimum marks is to be scored in each of the 8 subjects for passing. In how many ways a student can fail?
(1) 127
(2) 63
(3) 255
(4) 256
(5) None of these
8. A man can row at 10 kmph in still water. If the river flows at 3 kmph and, it takes 12 hours more in upstream than to go downstream for the same distance. How far is the place?
(1) 160 km
(2) 164 km
(3) 170 km
(4) 175 km
(5) None of these
9. A alone would take 6 hours more to complete the job than if both A and B would work together. When B worked alone he took 1.5 hours more to complete the job and A and B worked together. How much time they will take if they work together?
(1) 3 hours
(2) 4 hours
(3) 4.5 hours
(4) 5 hours
(5) None of these
10. From a pack of 52 cards, 2 cards are drawn randomly. What is probability that it has one King and one Jack?
(1) 7/663
(2) 8/663
(3) 11/663
(4) 13/663
(5) None of these
11. A two-digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is
(1) 18
(2) 24
(3) 81
(4) 42
(5) None of these
ANSWERS
7. (3) ;
The students can fail in 1, 2, 3, 4, 5, 6, 7, 8 subjects.
So the number of ways he can fail is
8C1 + 8C2 + 8C3 + 8C4 + 8C5 + 8C6 + 8C7 + 8C8
= 8 + 28 + 56 + 70+56 + 28 + 8 + 1 = 255
8. (5); Let distance be = x
x/(10 - 3) - x/(10 + 3) = 12
x/7 - x/13 = 12
(13x - 7x)/ 91 = 12
6x/91 = 12
x = 182 km
9. (1)
10. (2) ;
n (S) = 52C2 = 51 × 26
n (E) = 4C1 × 4C1 = 4 × 4
p (E) = 16/51*26 = 8/663
11. (4)
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