Directions (Q. 1 - 5): Each question below is followed by two statements I and II. You are to determine whether the data given in the statement is sufficient to answer the question. You should use the data and your knowledge of Mathematics to choose among the possible answers.
Give answer—
1) If the statement I alone is sufficient to answer the question, but the statement II alone is not sufficient.
2) If the statement II alone is sufficient to answer the question, but the statement I alone is not sufficient.
3) If both statements I and II together are needed to answer the question.
4) If either the statement I alone or the statement II alone is sufficient to answer the question.
5) If you cannot get the answer from the statements I and II together, but need even more data.
1. A man covers a distance by car. How many kilometer does he cover?
I. Had he moved 10 kmph faster, he would have taken one hour less.
II. Had he moved 8 kmph slower, he would have taken one hour more.
2.√ ((x – y)/x)
I. x/y = 4/3
II. y = 3
3. Find the three consecutive positive integer.
I. If their product is 120.
II. If their sum is 15?
4. What is the area of a equilateral triangle?
I. Height of the triangle is 8 m.
II. Co-ordinates of two vertices are (3, 3) & (7, 5).
5. Two trains are moving on parallel tracks in opposite direction. In how many seconds will the trains cross each other completely?
I. Ratio of their speeds is 3 : 4.
II. First train crosses a pole in 5 seconds and second train crosses the pole in 6 seconds.
Directions (Q. 6- 10): Following line graph shows percentage profit of two companies A and B over the years 2000-2005. Answer the given questions based on this graph?
6. If in year 2002, the expenditure of Company B was Rs 45 lakhs, then what is the income of Company B in the same year?
1) 50 lakhs
2) 52 lakhs
3) 54 lakhs
4) 55 lakhs
5) 60 lakhs
7. For how many years the difference of the net profit for two companies was the maximum?
1) 1
2) 2
3) 3
4) Data inadequate
5) None of these
8. If, for Company A, the expenditure in year 2000 and 2002 was 1.2 crores together, then what is the total income in these years?
1) 1.86 crores
2) 1.8 crores
3) 1.92 crores
4) Data inadequate
5) None of these
9. In how many years, the total income is less than double the total expenditure in that year for Company B?
1) 1
2) 2
3) 3
4) 4
5) 5
10. If the income of Company A in 2000 and Company B in 2004 is same Rs 42 lakhs, then what is the total expenditure of Company A in 2000 and Company B in 2004?
1) 52 lakhs
2) 64 lakhs
3) 56 lakhs
4) 60 lakhs
5) None of these
ANSWERS
Income = 45 + 9 = 54 lakhs
Expenditure = Income – Profit = 42 – 14 = 28 lakhs
Expenditure = 42 – 18 = 24 lakhs
Total expenditure = 28 + 24 = 52 lakhs
1. 3;
Let the distance be D km. Time is T hours. Speed = S km/hr.
Using Statement I:
D = S × T = (S + 10) (T – 1) S = 10T – 10
Using Statement II:
D = S × T = (S – 8) (T + 1) S = 8T + 8
Using Both:
10T – 10 = 8T + 8 T = 9 Hours, S = 80 km/hr
D = 9 × 80 = 720 Km
So the Answer is (3) ie., using both statements together.
2. 1
√((x - t)/ x) = √(1 – (y/x))
3. 4;
From statement I alone we can find a unique solution as it is given that three integers are consecutive and positive with product 120. So the unique integers will be 4, 5, 6.
From statement II alone we can find a unique solution.
Let the positive integers be a, a + 1, a + 2.
So, a + a + 1 + a + 2 = 15
a = 4 and the integers are 4, 5, and 6.
4. 4; Using Statement I:
We know height of equilateral triangle is .
Here height is given so we can find the side and hence the area of triangle.
Using Statement II:
As the co-ordinates of two vertices are given we can find the length of the side of the triangle and hence the area of the equilalteral triangle.
5. 3; Let the length of trains be L1 and L2.
Using Statement I:
We can only find their speeds as 3x and 4x.
Using Statement II:
We can find L1 = 5 × Speed of Trains,
L2 = 6 × Speed of second Trains
Using Both:
L1 = 5 × 3x
L2 = 6 × 4x
Required time to cross each other completely is
(L1 + L2)/ (3x + 4x) = (15x + 24x)/ 7x = 39/7
Hence, the answer is (3).
6. 3; Profit = (Profit % * Expenditure)/100 = (20*45)/100 = 9
7. 4; Data is not sufficient.
8. 4; Data inadequate.
9. 5; (Income - Expenditure)/ Exp*100= P%
Expenditure is 100% in each year and Income% = Exp% + Profit%
Expenditure is 100% in each year and Income% = Exp% + Profit%
10. 1; Profit of A in 2000 = (42*50)/150 = 14 lakhs
Profit of B in 2004 = (42*75)/175 = 18 lakhs
No comments:
Post a Comment