Quantitative Aptitude Quiz

Directions (Q. 1-5): What should come in place of question mark (?) in the following number series?

1. 5, 41, 321, 1921, 7681, 15361, ?
1) 21381
2) 23710
3) 22173
4) 23121
5) 1


2. 1, 3, 7, 13, 22, 34, 51, 71, 96, 124, ?
1) 137
2) 147
3) 157
4) 167
5) None of these

3. 664, 334, 85.5, 16.25, 4.03125, ?
1) 2.73012
2) 3.17203
3) 2.403125
4) 3.220175
5) None of these

4. 33, 110, 453, 2282, 13711, ?
1) 95673
2) 96747
3) 96312
4) 951321
5) 96000

5. 0.8, 3.8, 12.6, 44.8, 188.2, ?
1) 758.6
2) 868.8
3) 952.00
4) 1012.2
5) 1112.2

Directions (Q. 6-10): In the following questions two equation numbered I and II are given. You have solve the equation and give answer if-
1. x > y
2. x > y
3. x < y
4. x < y
5. x = y or the relationship cannot be established.

6.

I. 20x2 - 31x + 12 = 0

II. 20y2 - y - 12 = 0

7.

I. 3x2 - 47x + 184 = 0

II. 2y2 - 23y + 66 = 0

8.

I. 30x - 49√x + 20 = 0

II. 42y - 5√y - 25 = 0

9.

I. x²- 10√3x + 63 = 0

II. y² - √2y - 24 = 0

10.

I. x2 - 14x + 48 = 0

II. y2 - y - 30 = 0

ANSWERS:

1.   5; The series is:

5 × 10 – 9 = 41

41 × 8 – 7 = 321

321 × 6 – 5 = 1921

1921 × 4 – 3 = 7680

7681 × 2 – 1 = 15361

15361 × 0 – (–1) = 1

2.   3; The series is:

1 + 1 + 1 = 3

3 + 2 + 2 = 7

7 + 3 + 3 = 13

13 + 4 + 5 = 22

22 + 5 + 7 = 34

34 + 6 + 11 = 51

51 + 7 + 13 = 71

71 + 8 + 17 = 96

96 + 9 + 19 = 124

124 + 10 + 23 = 157

First is numbers (1, 2, 3, 4...) etc and second is prime numbers (1, 2, 3, 5, 7, 11, 13...).

3.   3; The series is:

664 + 4 ÷ 2 = 334

334 + 8 ÷ 4 = 85.5

85.5 + 12 ÷ 6 = 16.25

16.25 + 16 ÷ 8 = 4.03125

4.03125 + 20 ÷ 10 = 2.403125

4.   5; The series is:

13 × 2 + 7 = 300

33 × 3 + 11 = 110

110 × 4 + 13 = 453

453 × 5 + 17 = 2282

2282 × 6 + 19 = 13711

13711 × 7 + 23 = 96000

All are prime number >7.

5.   3; The series is:

0.8 × 1 + 3 = 3.8

3.8 × 2 + 5 = 12.6

12.6 × 3 + 7 = 44.8

44.8 × 4 + 9 = 188.2

188.2 × 5 + 11 = 952

6. 2; x ³y

I. 20 x2 – 31 x + 12 = 0

5x (4x-3) – 4 (4x – 3) = 0

(4x –3) (5 x – 4) = 0

x = 3/4, 4/5

II. 20 y2 – y –12 = 0

(5 y – 4 ) (4y + 3) = 0

y = 4/5, - 3/4

Ans is 2 X > Y

7.1; X > y

I. 3x2 – 47 x + 184 = 0

(x–8) (3x – 23) = 0

x = 8, 23/3

II. 2 y2 – 23 y + 66 = 0

(y–6) (2 y –11) = 0

y = 6, 11/2

8.2;

I. 30 x – 25 x + 20

(5√x– 4) (6√x– 5) = 0

x = 16/25, x = 25/36

II. 42 y – 5√y– 25 = 0

(6 √y– 5) (7√y + 5) = 0

y = 25/36, y = 25/49

Ans is 2 X > Y

9  5; no relation can be established

I.x2 – 10√3+ 63 = 0

x2 – 10√3+ 63 = 0

( x – 3√3 ) (x –7√3)= 0

x = 3√3, 7√3

II. y2 – √2y – 24 = 0

(y – 4√2) (y + 3√2) = 0

y = 4√2, -3√2

10 . 2;x ³y

I. x2 – 14 x – 48 = 0

(x– 6 ) (x – 8) = 0

x = 6, 8

II. y2 – y – 30 = 0

(y + 5) (y - 6) = 0

y = -5 , 6